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Home/ Questions/Q 8265911
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T04:58:05+00:00 2026-06-08T04:58:05+00:00

Using awk I want to get columns starting with /acq/old/* . file1 z y

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Using awk I want to get columns starting with /acq/old/*.

file1

z y x / ACQ / old / a.zip y
z y t / ACQ / old / a.zip x

The fourth column

file2

z y / ACQ / old / a.zip 10
z y / ACQ / old / a.zip 20

the third column

…

file n

z y w t / ACQ / old / x.zip 100
z y f r / ACQ / old / w.zip 200

The fifth column

I want to do following an operation.

for myfile in ls *. txt
do
  awk '??' $ myfile
  other processes
done
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T04:58:06+00:00Added an answer on June 8, 2026 at 4:58 am

    You can use sed to get rid of leading columns:

    sed 's@^[^/]*@@' input
    

    This is awk solution:

    awk -F/ -vOFS=/ '{$1=""}1' input
    
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