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Home/ Questions/Q 6232013
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T10:02:32+00:00 2026-05-24T10:02:32+00:00

Using Boost.Python, is there a way to call a Python function that’s been passed

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Using Boost.Python, is there a way to call a Python function that’s been passed through a weakref? The following code doesn’t work:

import weakref

def foo():
    print 'it works'

def func():
    return weakref.ref(foo)

The following is the C++:

object module = import("test");
object func(module.attr("func"));
object foo = func();
foo(); // Should print 'it works', but it prints nothing

However, if I pass the function object without weakref, it all works fine. Is there any way to make this work?

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  1. Editorial Team
    Editorial Team
    2026-05-24T10:02:32+00:00Added an answer on May 24, 2026 at 10:02 am

    From weakref documentation:

    Return a weak reference to object. The original object can be retrieved by calling the reference object if the referent is still alive…

    So, given your snippet:

    import weakref
    
    def foo():
        print "It Works!"
    
    def func():
        return weakref.ref(foo)
    
    ref = func() # func returns the reference to the foo() function
    original_func = ref() # calling the reference returns the referenced object
    original_func() # prints "It Works!"
    
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