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Home/ Questions/Q 8051439
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T07:18:16+00:00 2026-06-05T07:18:16+00:00

Using Castle Windsor I can register multiple implementations of a type e.g. container.Register(Component.For<IMyInterceptor>() .ImplementedBy<MyInterceptor>();

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Using Castle Windsor I can register multiple implementations of a type e.g.

container.Register(Component.For<IMyInterceptor>()
    .ImplementedBy<MyInterceptor>();

container.Register(Component.For<IMyInterceptor>()
    .ImplementedBy<MyInterceptor2>();

This all works as you’d expect and I can resolve multiple implementations using ResolveAll()

If I try to register an instance of another implementation at runtime though – e.g.

var interceptor = new MyInterceptor3();
Container.Register(
    Component.For<IMyInterceptor>()
        .Instance(interceptor));

I get an exception:

There is a component already registered for the given key MyInterceptor3

Is this the expected behaviour? What I’m trying to acheive is to use e.g. Container.ResolveAll() to get a list of default implementations of IMyInterceptor plus optional additional implementations (i.e. on a request by request basis, when debug modes are enabled).

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  1. Editorial Team
    Editorial Team
    2026-06-05T07:18:16+00:00Added an answer on June 5, 2026 at 7:18 am

    This will sort you out.

    var interceptor = new MyInterceptor3();
    Container.Register(
        Component.For<IMyInterceptor>()
            .Instance(interceptor).Named("something unique));
    

    Names must be unique.

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