Question

Using: javax.xml and org.w3c:

public void removeNodeFromXML(File xmlfile_, String uuid)
  {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    Document doc = builder.parse(xmlfile_);

    TransformerFactory tFactory = TransformerFactory.newInstance();
    Transformer tFormer = tFactory.newTransformer();

   //????

   Element rootElement = doc.getRootElement();
   rootElement.removeChild("1236");

   //???

   // Normalize the DOM tree to combine all adjacent nodes
   doc.normalize();
   Source source = new DOMSource(doc);
   Result dest = new StreamResult(xmlfile_);
   tFormer.transform(source, dest);

  }

XML looks like this

<Servers>
 //remove this guy
 <server ID="1236">
  <name>Josh</name>
  <port>1234</port>
  <ip>12.2.2.3</ip>
 </server>

<server ID="1237">
  <name>John</name>
  <port>1234</port>
  <ip>12.2.2.3</ip>
 </server>
</Servers>

Answer 1

You can use XPath to select specific elements/attributes. Just search the web for Tutorials. Here is good one. You should also read the Java-Doc for java.xml.xpath, which includes short examples.

The XPath-Expression for your XML-File is: /server[@ID='xxxx']