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Home/ Questions/Q 8499827
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T00:46:24+00:00 2026-06-11T00:46:24+00:00

Using jQuery, how can I iterate over an object, and get the unique values

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Using jQuery, how can I iterate over an object, and get the unique values of a key with a count of each value?

For example, for this array:

var electrons = [
    { name: 'Electron1', distance: 1 }, 
    { name: 'Electron2', distance: 1 }, 
    { name: 'Electron3', distance: 2 }, 
    { name: 'Electron4', distance: 2 }, 
    { name: 'Electron5', distance: 2 }, 
    { name: 'Electron6', distance: 2 }, 
    { name: 'Electron7', distance: 2 }, 
    { name: 'Electron8', distance: 2 }, 
    { name: 'Electron9', distance: 2 }, 
    { name: 'Electron10', distance: 2 }, 
    { name: 'Electron11', distance: 3 }, 
];

I’d like to get back the following:

var distance_counts = {1: 2, 2: 8, 3: 1};

I’ve got this, which works but is a bit clumsy:

var radius_counts = {};
for (var i = 0; i < electrons.length; i++) { 
    if (electrons[i].distance in radius_counts) { 
         radius_counts[electrons[i].distance] += 1;
    } else { 
         radius_counts[electrons[i].distance] = 1;
    } 
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T00:46:25+00:00Added an answer on June 11, 2026 at 12:46 am

    you could use map for this purpose as:

    var distances = {};
    $.map(electrons,function(e,i) {
       distances[e.distance] = (distances[e.distance] || 0) + 1;
    });
    

    or

    var distances = {};
    $.each(electrons,function(i,e) {
       distances[this.distance] = (distances[this.distance] || 0) + 1;
    });
    

    Also may I point out to you that although this code good to look and compact, this is not generally faster. Better make your code more faster and more easy to look at as:

    var distances = {},e;
    for (var i = 0,l=electrons.length; i < l; i++) { 
        e = electrons[i];
        distances[e.distance] = (distances[e.distance] || 0) + 1;
    }
    
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