Question

Using JQuery I am trying to chain a couple of functions when an element has a hover state.

I would normally use the .hover event function, but after reading some tutorials I read that using .on is better as you can use one event handler to monitor all bubbling events within a document.

However, I am having problems when I chain two functions together like so:

$("element").on( "hover", function() {         
    console.log("one");     
}, function() {         
    console.log("two");     
});

I expected the result to be one two (which was the case when using .hover) but instead I get two two.

Can anyone explain what I am doing wrong or whether this is expected behaviour and why?

Reproduced using .hover(...): http://jsfiddle.net/gXSdG/

Reproduced using .on(hover...): http://jsfiddle.net/gXSdG/1/

Answer 1

.on() can only take 1 function, so you have to interrogate the passed event to check what the event was. Try this:

$("element").on("hover", function(e) {
    if (e.type == "mouseenter") {
        console.log("one");   
    }
    else { // mouseleave
        console.log("two");   
    }
});

Example fiddle

Alternatively you can split the two events which constitute the hover() method – mouseenter and mouseleave:

$("#element").on("mouseenter", function() {
  console.log("one");   
}).on('mouseleave', function() {
  console.log("two");   
});

#element {
  background-color: black;
  height: 100px;
  margin: 100px;
  width: 100px;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="element"></div>