Question

Using jQuery, I loaded an enrollment_forms.php page into a div called container_level2. When the enrollment_forms.php page is loaded in this container_level2 I want to call another function.

How can I do this using one function with parameters?

Here is a function I’ve made:

function view_update_load_form(list_index, student_id){
     $.ajax({
            url: "enrollment_forms.php",
            success: function(result){
                $('#container_level2').html(result);
            },
            complete: function(){
                load_form(list_index, student_id);
            }
            }); 
}       

In the above code I call function with two parameters:

view_update_load_form(list_index, student_id)

This function loads a page:

enrollment_forms.php.

when enrollment.forms.php is loaded, I want to call second function:

load_form(list_index, student_id)

with same paramters.

How can I? This doesn’t work.
It often calls 2nd function even if page is not completely loaded.

Answer 1

You could put the load_form call inside your success function:

success: function(result){
    $('#container_level2').html(result);
    load_form(list_index, student_id);
},

That way it won’t be called before inserting the html.