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Home/ Questions/Q 6728223
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:08:38+00:00 2026-05-26T10:08:38+00:00

Using jQuery: var $activeList = $(‘.active_list’); var $activeSlide = $activeList.find(‘.active_list_slide’); var slideIndex = $activeList.children().index($activeSlide);

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Using jQuery:

        var $activeList = $('.active_list');
        var $activeSlide = $activeList.find('.active_list_slide');
        var slideIndex = $activeList.children().index($activeSlide);

In the case above, $activeList was used twice. Was it worth it to make it a variable rather than just keeping it as $('.active_list').

My general rule was always that 2 uses of a dynamic variable make it worth it to make a variable (rather than doing the same operation to find it twice). Is this a good philosophy?

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:08:38+00:00Added an answer on May 26, 2026 at 10:08 am

    Certainly. You’ll avoid what is potentially a lot of code execution behind that query. The only exception is if somehow the result might have changed from one call to the next. Doesn’t seem very likely in this context, though. This is DOM manipulation, not massively concurrent database updates.

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