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Home/ Questions/Q 5841207
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T11:51:36+00:00 2026-05-22T11:51:36+00:00

Using Lift’s json parser, how can I output parsed json objects into a template?

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Using Lift’s json parser, how can I output parsed json objects into a template?

The datatypes that net.liftweb.json.JsonParser provides are not
standard lists.

package rem.lift_client
package snippet
import net.liftweb._

import util._
import Helpers._
import net.liftweb.json.JsonParser._

class SearchResults {

  def render() = {
    val json_raw = "[ {\"userName\":\"John\"}, {\"userName\":\"Michael\"} ]"
    val json_parsed = parse(input)
    "li *" #> json_parsed.toString <---- NOT CORRECT
   }
 } 

In the above example, I wanted to output a list of users as:

  • John
  • Michael
  • How do I interpret the parsed object? Any ideas are welcome, thanks.

    NOTE: In addition to the accepted answer, lift-json has an excellent documentation on this subject.

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    1. Editorial Team
      Editorial Team
      2026-05-22T11:51:36+00:00Added an answer on May 22, 2026 at 11:51 am

      One way is to extract the data with case classes.

      implicit val formats = DefaultFormats
      case class User(userName: String)
      json_parsed.extract[List[User]]
      
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