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Home/ Questions/Q 568083
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:09:06+00:00 2026-05-13T13:09:06+00:00

Using lxml.objectify like so: from lxml import objectify o = objectify.fromstring(<a><b atr=’someatr’>oldtext</b></a>) o.b =

  • 0

Using lxml.objectify like so:

from lxml import objectify

o = objectify.fromstring("<a><b atr='someatr'>oldtext</b></a>")

o.b = 'newtext'

results in <a><b>newtext</b></a>, losing the node attribute. It seems to be directly replacing the element with a newly created one, rather than simply replacing the text of the element.

If I try to use o.b.text = 'newtext', it tells me that
attribute 'text' of 'StringElement' objects is not writable.

Is there a way to do this within objectify without having to split it out into a different element and involving etree? I simply want to replace the inner text while leaving the rest of the node alone. I feel like I’m missing something simple here.

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:09:06+00:00Added an answer on May 13, 2026 at 1:09 pm
    >>> type(o.b)
    <type 'lxml.objectify.StringElement'>
    

    You are replacing an element with a plain string. You need to replace it with a new string element.

    >>> o.b = objectify.E.b('newtext', atr='someatr')
    

    For some reason you can’t just do:

    >>> o.b.text = 'newtext'
    

    However, this seems to work:

    >>> o.b._setText('newtext')
    
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