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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T23:59:04+00:00 2026-05-11T23:59:04+00:00

Using NH 2.0, I have a custom type. It is composed of four properties,

  • 0

Using NH 2.0, I have a custom type. It is composed of four properties,
so I implemented ICompositeUserType.

I want to specify length and precision for the string and decimal properties within the user type, to avoid specifying it with every usage in the mapping files.

But there is only a PropertyTypes property to implement, which returns
IType. The funny thing is, the IUserType has a SqlTypes property,
ICompositeUserType does not.

  • Do I have to implement both interfaces?
  • Do I have to implement a user type to wrap each sql-type I want to
    specify?
  • Or how can I specify the Sql type for a composite user type?

Thanks a lot.

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  1. Editorial Team
    Editorial Team
    2026-05-11T23:59:04+00:00Added an answer on May 11, 2026 at 11:59 pm

    I found the solution, it is pretty simple. I have to create the NHibernate types using the TypeFactory:

    public IType[] PropertyTypes
    {
      get
      {
        return new []
        {
          TypeFactory.GetDecimalType(36, 18),
          TypeFactory.GetStringType(100)
        }
      }
    }
    
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