Question

Using Python I need to insert a newline character into a string every 64 characters. In Perl it’s easy:

s/(.{64})/$1\n/

How could this be done using regular expressions in Python?
Is there a more pythonic way to do it?

Answer 1

Same as in Perl, but with a backslash instead of the dollar for accessing groups:

s = "0123456789"*100 # test string
import re
print re.sub("(.{64})", "\\1\n", s, 0, re.DOTALL)

re.DOTALL is the equivalent to Perl’s s/ option.