Question

Using Rails and MySQL. Not sure if this has been asked, but couldn’t find it.

I have the following records:

1. I love Rails
2. I love Django
3. I code using Ruby on Rails

====

(1) Search: “i love”

Results: “I love Rails”, “I love Django”

====

(2) Search: “love”

Results: “I love Rails”, “I love Django”

====

(3) Search: “ails”

Results: “I love Rails”, “I code using Ruby on Rails”

====

(4) Search: “code Ruby”

Results: “I code using Ruby on Rails”

====

My code is:

term = "%#{params[:term]}%"
shops = Shop.where("name LIKE ?", term)

It only works on Search (1) and (2). How can I code to achieve results when doing search (3) and (4) too?

Many thanks.

Answer 1

Found the solution.

I need to wrap each word in the search phrase with %string%.

====

Search (1): “i love”

Query: SELECT * from t WHERE name LIKE "%i% %love%";

Results: “I love Rails”, “I love Django”

====

Search (2): “love”

Query: SELECT * from t WHERE name LIKE "%love%";

Results: “I love Rails”, “I love Django”

====

Search (3): “ails”

Query: SELECT * from t WHERE name LIKE "%ails%";

Results: “I love Rails”, “I code using Ruby on Rails”

====

Search (4): “code Ruby”

Query: SELECT * from t WHERE name LIKE "%code% %Ruby%";

Results: “I code using Ruby on Rails”

====

My Ruby code should be:

term = "#{params[:term]}"
f_term = term.gsub /\b/, '%'
shops = Shop.where("name LIKE ?", f_term)

You can test this at http://sqlfiddle.com/#!2/d63f5/4