Home/ Questions/Q 8527889
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-11T08:40:50+00:00

Using regular expressions in C#, VS 2010. Here’s the code. static string capturePattern =

  • 0

Using regular expressions in C#, VS 2010. Here’s the code.

static string capturePattern = @"\|([!-|]{2})([!-|]{2})([!-|]{2})?([!-|]{2})?([!-|]{2})?([!-|]{2})?([!-|]{2})?\|";

Regex rgx = new Regex(capturePattern);

string TS="!3829.87N/12033.82Wv169/000|!('d%*|"

MatchCollection matches = rgx.Matches(TS);

matches.Count ends-up being 1 and matches[0] is “|!(‘d%*|”.

I was expecting matches.Count to be 3, and parsed strings to be:

matches[0] = "!("
matches[1] = "'d"
matches[2] = "%*"

What did I do wrong?

Chuck

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Your regex captures everything between the bars | into a single match. If you want the parts in parenthesis, those are in match[0].Groups.

    Group[0] is the whole capture group. Groups 1, 2, and optionally, 3 and more are going to be the character pairs in parenthesis.

    In your case, matches.Count will be 1, matches[0].Groups.Count will be 4, with :

    matches[0].Group[1] == "!(" 
matches[0].Group[2] == "'d" 
matches[0].Group[3] == "%*"
    • 0