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Home/ Questions/Q 691413
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:32:27+00:00 2026-05-14T02:32:27+00:00

Using ruby regexp I get the following results: >> ‘foobar'[/o+/] => oo >> ‘foobar'[/o*/]

  • 0

Using ruby regexp I get the following results:

>> 'foobar'[/o+/]
=> "oo"
>> 'foobar'[/o*/]
=> ""

But:

>> 'foobar'[/fo+/]
=> "foo"
>> 'foobar'[/fo*/]
=> "foo"

The documentation says:
*: zero or more repetitions of the preceding
+: one or more repetitions of the preceding

So i expect that ‘foobar'[/o*/] returns the same result as ‘foobar'[/o+/]

Does anybody have an explanation for that

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:32:28+00:00Added an answer on May 14, 2026 at 2:32 am

    'foobar'[/o*/] is matching the zero os that appear before the f, at position 0
    'foobar'[/o+/] can’t match there because there needs to be at least 1 o, so it instead matches all the os from position 1

    Specifically, the matches you are seeing are

    'foobar'[/o*/] => '<>foobar'
    'foobar'[/o+/] => 'f<oo>bar'

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