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Home/ Questions/Q 149105
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Asked: May 11, 20262026-05-11T09:04:36+00:00 2026-05-11T09:04:36+00:00

Using some extensions provided by .net, one can find groups of parenthesis by using

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Using some extensions provided by .net, one can find groups of parenthesis by using something like this:

^(\w+)\(((?>[^()]+|\((?<D>)|\)(?<-D>))*(?(D)(?!)))\)(.*)$ 

This will match the following:

Func(innerfunction(arg)).DoSomething() 

With the following groups:

  • Group 1: Func
  • Group 2: innerfunction(arg)
  • Group 3: .DoSomething()

My question is, how do I match commas, taking into account if they are or not inside a parenthesis group? For example, a regex to evaluate:

Func(innerFunction(arg1, arg2), arg3).DoSomething() 

Should yield:

  • Group 1: Func
  • Group 2: innerFunction(arg1, arg2)
  • Group 3: arg3
  • Group 4: .DoSomething()

Thanks.

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  1. 2026-05-11T09:04:37+00:00Added an answer on May 11, 2026 at 9:04 am

    I think I found it. Does anyone have a counter example:

    ^([^()]*?|.*\((?>[^()]+|\((?<D>)|\)(?<-D>))*(?(D)(?!))\).*?),(.*)$ 

    This will match this expression:

    func1(arg2, func3(arg3, arg4)), func2(arg5, arg6).property 

    as:

    • Group1: func1(arg2, func3(arg3, arg4))
    • Group2: func2(arg5, arg6).property

    This solution only looks for one comma, but it deals with an arbitrary depth of parenthesis.

    UPDATE: Gumbo has provided a counter-example:

    func1((arg1), arg2), func2(arg3).property 

    Get’s split up into:

    • Group1: func1((arg1)
    • Group2: arg2), func2(arg3).property

    HOWEVER: By turning the first ‘any match’ into non-greedy, one can solve it:

    ^([^()]*?|.*?\((?>[^()]+|\((?<D>)|\)(?<-D>))*(?(D)(?!))\).*?)\s*,\s*(.+)$ 

    Any other counter-example?

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