Question

Using SQL Server 2000

table1

id date time

001 01/02/2012 02:00
001 02/02/2012 01:00
001 07/02/2012 08:00
002 04/02/2012 01:00
002 15/02/2012 06:00
...

from the table1 i want to get the second record onwards for each id order by date column

Expected Output

id date time

001 02/02/2012 01:00
001 07/02/2012 08:00
002 15/02/2012 06:00
...

How to make a query for getting the second record onwards.

Need sql query help

Answer 1

How about something like

SELECT  yt.*
FROM    your_table yt INNER JOIN
        (
            SELECT  [id],
                    MIN([datetime]) first_datetime
            FROM    your_table
            GROUP BY    [id]
        ) f ON  yt.id = f.id
            AND yt. [datetime] > f.first_datetime

Assuming first record is the min date per ID.