Question

Using SQL Server 2000

Table1

ID Date Value1 Value2

001 01/01/2012 100 0
001 02/01/2012 200 200
...
...
001 31/01/2012 250 0
002 01/01/2012 050 100
002 02/01/2012 100 0
...
002 31/01/2012 075
....

I want to display the value (value1 column) by date wise (date column) group by id

Output like

ID 01/01/2012 02/01/2012 ... 31/01/2012

001  100 200 .... 250
002  050 100 .... 075
.....

Query

DECLARE @loop int,@date Date,@sql nvarchar(4000)
DECLARE @TempTable TABLE
(
  [Date] DATE
)
INSERT INTO @TempTable SELECT DISTINCT [Date] FROM table1 ORDER BY [Date]
  SET @sql = ''
  SET @loop = 1
  WHILE (@loop<=31)
    BEGIN
        IF EXISTS(SELECT * FROM @TempTable WHERE DAY([Date])=@loop) 
        BEGIN
            SET @date = (SELECT [Date] FROM @TempTable WHERE DAY([Date])=@loop)
            SET @sql = @sql+ ',MAX(CASE CONVERT(nvarchar(10),[Date],103) WHEN '''+CONVERT(nvarchar(10),@date,103)+''' THEN [Value1] END) AS [DATE'+CONVERT(nvarchar(2),@loop)+']'
         END
         ELSE
            SET @sql = @sql+ ', NULL AS [DATE'+CONVERT(nvarchar(2),@loop)+']'
         SET @loop = @loop+1
    END 

EXEC('SELECT ID'+@sql+' FROM table1 GROUP BY ID')

The above query is working, from the above query i want to find the sunday, if it is sunday then date column should display a value from value2 column otherwise value1 column
should display

How to do this.

Need Query help

Answer 1

DATEPART function gives you integer day of the week. Sunday – Saturday become 1 – 7.

try change the line by this one

SET @sql = @sql+ ',MAX(CASE CONVERT(nvarchar(10),[Date],103) WHEN '''+CONVERT(nvarchar(10),@date,103)+''' THEN CASE DATEPART(weekday,[Date])WHEN 1 THEN [Value1] ELSE [Value2] END END) AS [DATE'+CONVERT(nvarchar(2),@loop)+']'

For total calculation per id

SELECT ID,
SUM(CASE WHEN DATEPART(weekday,[Date]) <> 1 THEN [Value1] END) AS Value1,
SUM(CASE DATEPART(weekday,[Date]) WHEN 1 THEN [Value2] END) AS Value2,
FROM table1 GROUP BY ID