Question

Using: SQL Server 2008 R2

I’d like to write a query that will select (ordered, in a single column) every second in a day in datetime format.

Ex.

2012-02-02 00:00:00
2012-02-02 00:00:01
2012-02-02 00:00:02
2012-02-02 00:00:03
2012-02-02 00:00:04
...
2012-02-02 23:59:58
2012-02-02 23:59:59

Yeah, seriously.

I can make a numbers table if need be, which might be helpful if I can convert integer values to datetime.

Thanks in advance.

Answer 1

This assumes a numbers table with values up to 86,400… the number of seconds in a day.

To illustrate, I create a numbers table here… but you should do this ahead of time.

SET NOCOUNT ON

DECLARE @YourDate DATETIME
SET @YourDate = '2/2/2012'

DECLARE @Numbers TABLE (Number INT)
DECLARE @Index INT

SET @Index = 0
WHILE (@Index < 86400)
BEGIN
    INSERT INTO @Numbers VALUES (@Index)
    SET @Index = @Index + 1
END

SELECT DATEADD(SECOND, n.Number, @YourDate)
FROM @Numbers n
WHERE n.Number < 86400