Question

Using Symfony I created a form in the backend. I have a submit button, which is used to save the form. I need to add another link (besides submit button) to the form that is supposed to send form data like submit button. Via this link I will be working on the submitted data via another method in the controller.

I have tried link_to('Link', '/backend_dev.php/question/edit?id='.$question->getId(), array('post' => true)) and link_to('Link', '/backend_dev.php/question/edit?id='.$question->getId(), array('method' => 'post')), but these functions do not send form data.

Controller

public function executeSave(sfWebRequest $request)
{
    $this->form = new SomeForm(SomePeer::retrieveByPk($request->getParameter('id')));
    if($request->isMethod('post'))
    {
        $this->form->bind($request->getParameter('some'), $request->getFiles('some'));
        if ($this->form->isValid())
        {
            $some = $this->form->save();
            $this->redirect('some/edit?id='.$some->getId());
        }
    }
}

public function executeLink(sfWebRequest $request)
{
    // Like executeSave I need form data here
}

Answer 1

Use jQuery with an onClick event on the link which will change the action attribute of the form and submit it. Assuming the link has an id myLink and the form an id myForm:

$('#myLink').click(function(e){
    $('#myForm').attr('action','<?php echo '/backend_dev.php/question/edit?id='.$question->getId()?>';
    $('#myForm').submit();
    e.preventDefault();
});