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Home/ Questions/Q 8972385
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T18:12:24+00:00 2026-06-15T18:12:24+00:00

Using the code sscanf(argv[1], "%d", &num1); sscanf(argv[2], "%c", &op); sscanf(argv[3], "%d", &num2); if ((op

  • 0

Using the code

    sscanf(argv[1], "%d", &num1);
    sscanf(argv[2], "%c", &op);
    sscanf(argv[3], "%d", &num2);

        if ((op != '-')||(op != '*')||(op != '/')||(op != '+'))
    {
        puts("Error:");
        printf("'%c' is not a valid operator", op);
        return 0;
    }

Compiles fine.

However, does not work for any input. For instance when the input is 4 + 7

Console prints:

Error:

‘+’ is not a valid operator

Edit: without this error checking code, the rest of the programme operates correctly, including a switch statement based on op!

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  1. Editorial Team
    Editorial Team
    2026-06-15T18:12:25+00:00Added an answer on June 15, 2026 at 6:12 pm

    Makes sense, since your condition is always true.

     (op != '-')||(op != '*')||(op != '/')||(op != '+')
    

    or even

     (op != '-')||(op != '*')
    

    will always evaluate to true.

    You’re basically saying “If op is not - OR op is not *… do whatever”.

    You probably meant to use && instead.

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