Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9146677
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T10:48:19+00:00 2026-06-17T10:48:19+00:00

Using the following code in Ruby: if (tickFormat.length > 12 && tickFormat.length < 24)

  • 0

Using the following code in Ruby:

if (tickFormat.length > 12 && tickFormat.length < 24)
    i = 1
    while(i < tickFormat.length) do
        if (i%2 != 0)
          tickFormat.at(i)[1] = ''
        end
        i++
    end
end

I get an “unexpected keyword_end” for the 2nd “end” statement. If I remove the while loop the code runs without error. Any ideas?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-17T10:48:20+00:00Added an answer on June 17, 2026 at 10:48 am

    Try this:

    if (tickFormat.length > 12 && tickFormat.length < 24)
      i = 1
      while(i < tickFormat.length) do
        if (i%2 != 0)
          tickFormat.at(i)[1] = ''
        end
        i += 1
      end
    end
    

    The i++ syntax doesn’t work in Ruby

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I get a warning with the following code using ruby 1.9.3-p194 if (x =
I'm using the following view code in my Ruby (1.9.3) on Rails (3.1) application
Using following code I try to get updated list of checkbuttons' corresponding text values,
I am using following code to get bitmap from url. This function is used
I am using following code to get source for image in wpf (image is
Using Rails 3.2.0.rc2 and ruby 1.9.3p0 In app/views/requests/_form.html.erb I have the following code for
I am using Ruby 1.8.6 for the following code: # Create an array and
Using Ruby 1.9.2, I have the following Ruby code in IRB: > r1 =
I'm using following code to configure logging in my Ruby on Rails application: environment.rb:
I am trying to compare two Ruby Hashes using the following code: #!/usr/bin/env ruby

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.