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Editorial Team
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Asked: 2026-06-01T07:43:05+00:00

Using the following example, I need to filter out the line containing ‘ABC’ only,

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Using the following example, I need to filter out the line containing ‘ABC’ only, while skipping the lines matching ‘ABC’ that contain square brackets:

2012-04-04 04:13:48,760~sample1~ABC[TLE 5332.233 2/13/2032 3320392]:CAST
2012-04-04 04:13:48,761~sample2~ABC
2012-04-04 04:13:48,761~sample3~XYZ[BAC.CAD.ABC.CLONE 232511]:TEST

Here is what I have, but so far I’m unable to successfully filter out the lines with square brackets:

bash-3.00$ cat Metrics.log | grep -e '[^\[\]]' | grep -i 'ABC'

Please help?

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1 Answer

  1. Editorial Team

    Edited based on comments:

    Try grep -i 'ABC' Metrics.log | grep -v "[[]" | grep -v "ABC\w"

    Input:

    2012-04-04 04:13:48,760~sample1~ABC[TLE 5332.233 2/13/2032 3320392]:CAST
2012-04-04 04:13:48,761~sample2~ABC
2012-04-04 04:13:48,761~sample3~XYZ[BAC.CAD.ABC.CLONE 232511]:TEST
2012-04-04 04:13:48,761~sample4~XYZ
2012-04-04 04:13:48,761~sample5~ABCD
2012-04-04 04:13:48,761~sample6~ABC:TEST

    Output:

    2012-04-04 04:13:48,761~sample2~ABC
2012-04-04 04:13:48,761~sample6~ABC:TEST
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