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Home/ Questions/Q 6350923
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T21:54:11+00:00 2026-05-24T21:54:11+00:00

Using the following function: function is_closure($t) { return ( !is_string($t) && is_callable($t)); } Can

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Using the following function:

function is_closure($t) { return ( !is_string($t) && is_callable($t)); }

Can this return true for anything else, than an anonymous closure function? If so, what would be the correct way to determine, if a variable is a closure?

Many thanks

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  1. Editorial Team
    Editorial Team
    2026-05-24T21:54:12+00:00Added an answer on May 24, 2026 at 9:54 pm

    The most deterministic way to check if a callback is an actual closure is:

    function is_closure($t) {
        return $t instanceof \Closure;
    }
    

    All anonymous functions are represented as objects of the type Closure in PHP. (Which, coming back to above comment, happen to implement the __invoke() method.)

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