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Home/ Questions/Q 796555
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T22:39:31+00:00 2026-05-14T22:39:31+00:00

Using the following pseudo-code: #define BUILD_PATH C:/MyBuild/ #define BUILD_NAME mydll.dll // Set build path

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Using the following pseudo-code:

#define BUILD_PATH "C:/MyBuild/"
#define BUILD_NAME "mydll.dll"
// Set build path here

representing how I would like to build the current project (a dll) into C:/MyBuild/mydll.dll, how would I accomplish this by only using preprocessor directives?

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  1. Editorial Team
    Editorial Team
    2026-05-14T22:39:31+00:00Added an answer on May 14, 2026 at 10:39 pm

    I may be misunderstanding, but I really cannot understand WHY you want to do this but it is doable:

    #pragma comment( linker, "/out:c:\mydll.dll" )
    

    I cannot re-iterate enough exactly how much you don’t want to be doing this though …

    If you want to GET the output path via pre-processor info then, I’m afraid … you can’t. That info comes from several steps after the pre-processor so there is no way the pre-processor could get that info.

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