Question

Using the method found here, I am collecting form values and posting them using the following code:

$.ajax({
    type: "POST",
    url: "http://"+document.domain+"/SimplaAdmin/includes/rpc.php",
    data: { data:postdata, method: 'addSite'},
    dataType: "json",
.......

Posted data is:

data:{
    "textfield": ["",""],
    "dropdown": ["option1","option1"],
    "siteTitle":"this is the site title",
    "siteKey":"",
    "siteurl":"",
    "address1":"",
    "address2":"",
    "address3":"",
    "landline":"",
    "method":"addSite",
    "small-input":"",
    "medium-input":"",
    "large-input":""
}

Then I try to get the value siteTitle using:

$data = $_POST['data'];
$obj=json_decode($data) ;
$title = $obj->{'siteTitle'};

But it does not work, where is the flaw in my thinking?

Answer 1

JSON was escaping the POST. Removed slashes and it worked.