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Home/ Questions/Q 7901009
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T09:06:39+00:00 2026-06-03T09:06:39+00:00

Using the OWASP checklist, which is the correct way protect this situation? This is

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Using the OWASP checklist, which is the correct way protect this situation? This is url inside of a javascript string where a url parameter needs to have xss protection.

Problem:

<script>
    var u = 'xyz.html?x=<% url.baddata %>'  
    dosomeAjax(u);
</script>

Possible solution 1:

var u = 'xyz.html?x=<% encodeForURL(url.baddata) %>'

Possible solution 2:

var u = 'xyz.html?x=<% encodeForJavaScript(url.baddata) %>'  

Possible solution 3:

var u = 'xyz.html?x=<% encodeForJavaScript(encodeForURL(url.baddata)) %>'  
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  1. Editorial Team
    Editorial Team
    2026-06-03T09:06:40+00:00Added an answer on June 3, 2026 at 9:06 am

    Solution 3 should be used:

    //solution 3:
    var u = 'xyz.html?x=<% encodeForJavaScript(encodeForURL(url.baddata)) %>';
    

    It is easier to see that this is correct if we rewrite the expression as:

    var u = '<% encodeForJavaScript("xyz.html?x=" + encodeForURL(url.baddata)) %>';
    

    First, we are creating a safe URL by appending baddata to a string constant, using the appropriate escape function. Then we are taking that safe URL and placing it in a JavaScript string, so we have to call the JavaScript escape function.

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