Question

Using this:

$db = mysqli_connect
(
    $db_host,
    $db_user,
    $db_pwd
) or die ("FATAL ! : The server ".$db_host." is not responding to ".$db_user."!");

how to get the $db value into this class (from include “class.php”) – without errors 😉

class User
{
    public $db;
    public $id;

    public function getUser()
    {
        if($this->id)
        {
            $sql = "
            SELECT
                users.*
            FROM
                users
            WHERE
                users.u_id='".$this->id."'
            ";
            $res = mysqli_query($db, $sql) or die(mysqli_error($db));
            $user_row = mysqli_fetch_object($db, $res);
            return $user_row;
        }
        else
        {
            return false;
        }
    }
    } // end class User

All I get is – well, nothing. Exept my main page loads empty… If I stop using the class, all is well (exept no data for the user is shown ;-))

Answer 1

when you instantiate the class (User), if you have already assigned the variable ($db)… you can do

$user = new User;
$user->db = $db;
$user->getUser();

yes AND inside your class when you are referencing properties of the class from its methods, use the $this notation… i.e. change $db to $this->db

that should work. you mentioned something about suppressing errors, that is a different issue. I am unsure what your goal is, but normal exception handling prior to the class’s instantiation would be adequate.