Question

Using type std::string to accept a sentence, for practice (I haven’t worked with strings in C++ much) I’m checking if a character is a vowel or not. I got this:

for(i = 0; i <= analyse.length(); i++) {
if(analyse[i] == 'a' || analyse[i] == 'e' [..etc..]) {
 ...vowels++;    
} else { ...
 ...consonants++;
}

This works fine if the string is all one word, but the second I add a space (IE: aeio aatest) it will only count the first block and count the space as a consonant, and quit reading the sentence (exiting the for loop or something).

Does a space count as no character == null? Or some oddity with std::string?, It would be helpful to know why that is happening!

EDIT:
I’m simply accepting the string through std::cin, such as:

std::string analyse = "";
std::cin >> analyse;

Answer 1

I’d guess you’re reading your string with something like your_stream >> your_string;. Operator >> for strings is defined to work (about) the same as scanf‘s %s conversion, which reads up until it encounters whitespace — therefore, operator>> does the same.

You can read an entire line of input instead with std::getline. You might also want to look at an answer I posted to a previous question (provides some alternatives to std::getline).