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Home/ Questions/Q 5998495
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:24:52+00:00 2026-05-23T00:24:52+00:00

Using underscore.js is there a way to breakout of the each if a certain

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Using underscore.js is there a way to breakout of the each if a certain condition is met?

_.each([1,2,3], function(value) {
  if (value == 2) {
    // continue 2
    return false;
  }
});

I’m sure returning false did the trick in prototype.js

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:24:53+00:00Added an answer on May 23, 2026 at 12:24 am

    Looks like you should return breaker, which isn’t in scope it seems. So, without modifying _, you can’t easily break out of iteration. The === there will ensure that returning {} won’t cause the loop to break; you need a reference to breaker, which you don’t have.

     // The cornerstone, an `each` implementation, aka `forEach`.
      // Handles objects implementing `forEach`, arrays, and raw objects.
      // Delegates to **ECMAScript 5**'s native `forEach` if available.
      var each = _.each = _.forEach = function(obj, iterator, context) {
        if (obj == null) return;
        if (nativeForEach && obj.forEach === nativeForEach) {
          obj.forEach(iterator, context);
        } else if (_.isNumber(obj.length)) {
          for (var i = 0, l = obj.length; i < l; i++) {
            if (i in obj && iterator.call(context, obj[i], i, obj) === breaker) return;
          }
        } else {
          for (var key in obj) {
            if (hasOwnProperty.call(obj, key)) {
              if (iterator.call(context, obj[key], key, obj) === breaker) return;
            }
          }
        }
      };
    
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