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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:06:29+00:00 2026-05-12T10:06:29+00:00

USING VB 6 My code. CommonDialog1.DialogTitle = Open File CommonDialog1.Filter = Database (1.mdb) |1.mdb

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USING VB 6

My code.

CommonDialog1.DialogTitle = "Open File"
CommonDialog1.Filter = "Database (1.mdb) |1.mdb"
CommonDialog1.FilterIndex = 1
CommonDialog1.Flags = cdlOFNFileMustExist + cdlOFNHideReadOnly
CommonDialog1.CancelError = True
On Error Resume Next
CommonDialog1.ShowOpen
If Err Then
    MsgBox "Select Database"
    Exit Sub
End If

I am using open dialog in my project. When I run the project I selected the file from the remote system.

Suppose if the remote system was not available, Next time when I select the open dialog, the open dialog should display the c Drive

Now it is displaying my Project folder, it should display the c Drive

How to write a code for this condition?

Need VB6 code Help.

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:06:30+00:00Added an answer on May 12, 2026 at 10:06 am

    This will solve what you are asking:

    To get FileSystemObject, you must add a reference in your project to ‘Microsoft Scripting Runtime’.

    Dim fs As New FileSystemObject
    Dim currentDir As String
    currentDir = fs.GetParentFolderName(CommonDialog1.FileName)
    If fs.FolderExists(currentDir) Then
        CommonDialog1.InitDir = currentDir
    Else
        CommonDialog1.FileName = ""
        CommonDialog1.InitDir = "C:\"
    End If
    

    EDIT:
    You must also set CommonDialog1.FileName = “”

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