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Home/ Questions/Q 8665063
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T17:23:35+00:00 2026-06-12T17:23:35+00:00

@using(Html.BeginForm(About, User, FormMethod.Post , new { id=aboutme})) { <fieldset> <ul> <li> <label class=block>About me</label>

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@using(Html.BeginForm("About", "User", FormMethod.Post , new { id="aboutme"}))
{
    <fieldset>
          <ul>
            <li> <label class="block">About me</label> @Html.TextAreaFor(m=>m.About.AboutMe)</li>
            <li> <input type="button" id="submit" class="input-button" /> </li>
          </ul>
    </fieldset>
}

<script type="text/javascript">
    $(function () {
        $('#submit').click(function () {

            $.ajax({
                url: this.action,
                type: this.method,
                data: $(this).serialize(),
                success: function (result) {
                    // The AJAX call succeeded and the server returned a JSON
                    // with a property "s" => we can use this property
                    // and set the html of the target div
                    alert(result.s);
                    $('#ShowResultHere').html(result.s);
                }
            });
            // it is important to return false in order to
            // cancel the default submission of the form
            // and perform the AJAX call
            return false;
        });
    }); 
</script>

When i debug this, action URL becoming /User/undefined.

How can i fix it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T17:23:36+00:00Added an answer on June 12, 2026 at 5:23 pm

    The this keyword refers to the source of the event, which is the submit button in this case. You want the form, so try this (using JQuery traversing):

    url: $(this).closest("form").prop("action"),
    type: $(this).closest("form").prop("method"),
    data: $(this).closest("form").serialize()
    

    The alternative would be to use <input type='submit' class='input-button' /> instead of the button, and listen for the event $("#aboutme").submit (that way this would actually refer to the form, as your code assumes).

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