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Home/ Questions/Q 8434625
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T06:42:29+00:00 2026-06-10T06:42:29+00:00

#!/usr/bin/perl $command=lscpu | grep -i Architecture; #$arch = system($command); @SplitArch = split(/:/, system($command)); print

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#!/usr/bin/perl
$command="lscpu | grep -i Architecture";
#$arch = system($command);
@SplitArch = split(/:/, system($command));
print @SplitArch[1];

The result I get is:

Architecture:          x86_64

I was hoping that the only thing that would display is:

x86_64
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  1. Editorial Team
    Editorial Team
    2026-06-10T06:42:30+00:00Added an answer on June 10, 2026 at 6:42 am

    This doesn’t do what you think it does. The system function runs the command and returns its exit status; so in your case, this:

    system($command)
    

    prints Architecture: x86_64, so this:

    @SplitArch = split(/:/, system($command));
    

    prints Architecture: x86_64 and sets @SplitArch to (0).

    print @SplitArch[1] then prints nothing, because @SplitArch has only one element. (By the way, you probably meant to write $SplitArch[1] rather than @SplitArch[1], but that’s neither here nor there.)

    Since you apparently intend to capture the output of $command, use `...` or qx/.../ instead:

    @SplitArch = split(/:/, `$command`);
    
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