Usually I open a new window like this: new Sensors(this).Show(); this.Hide(); But this method

Question

Asked: May 31, 20262026-05-31T13:17:18+00:00 2026-05-31T13:17:18+00:00

Usually I open a new window like this:

        new Sensors(this).Show();
        this.Hide();

But this method doesn’t work when I try to open a WPF window from a Form and vice versa, So I did this:

        System.Diagnostics.Process.Start(appAddress);
        this.Close();

The promblem when its done this way is that the debugger won’t debug the new Form/Window.

Is there a way to do this without having this problem?

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Editorial Team · Answer 1 · 2026-05-31T13:17:19+00:00

Editorial Team

Does this work (untested)?

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