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Home/ Questions/Q 6659133
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:59:46+00:00 2026-05-26T01:59:46+00:00

/* utf-8: 0xc0, 0xe0, 0xf0, 0xf8, 0xfc */ static unsigned char _mblen_table_utf8[] = {

  • 0
/* utf-8: 0xc0, 0xe0, 0xf0, 0xf8, 0xfc */
static unsigned char _mblen_table_utf8[] = 
{
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
    2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
    2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2,
    3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3,
    4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 1, 1
};

I bet it has something to do with the encodings,

but how exactly it works?

UPDATE

        while (str < ptr)
        {
            j = mblen[(*str)];
            tree_nput(r->tree, cr, sizeof(struct rule_item), str, j);
            str += j;
        }
    }   
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  1. Editorial Team
    Editorial Team
    2026-05-26T01:59:46+00:00Added an answer on May 26, 2026 at 1:59 am

    Because a character in a multibyte string has a variable length, this table maps each character to a length.

    The last 64 characters are wider than one byte, having lengths of 2 to 6.

    The usage would be something like that:

    unsigned char current_char = *mbstr;
    
    for (i = 0; i < _mblen_table_utf8[current_char]; i++) {
      /* treat *mbstr++ as a part of the current character */
    }
    
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