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Home/ Questions/Q 503497
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:24:00+00:00 2026-05-13T06:24:00+00:00

$value=’x-Cem-Date:Wed, 16 Dec 2009 15:42:28 GMT’; Right now I have: $value = preg_replace(‘/(^.+)(?=:)/e’, strtolower(‘\\1’),

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$value='x-Cem-Date:Wed, 16 Dec 2009 15:42:28 GMT';

Right now I have:

$value = preg_replace('/(^.+)(?=:)/e', "strtolower('\\1')", $value);

this outputs

$value='x-cem-date:wed, 16 dec 2009 15:42:28 GMT';

it should output:

$value='x-cem-date:Wed, 16 Dec 2009 15:42:28 GMT';
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  1. Editorial Team
    Editorial Team
    2026-05-13T06:24:01+00:00Added an answer on May 13, 2026 at 6:24 am

    Your regular expression should be as follows:

    /(^.+?)(?=:)/
    

    The difference is the +? character. The +? is non-greedy, meaning that it will find the LEAST amount of characters until the expression moves onto the next match in the expression, instead of the MOST characters until the next match.

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