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Home/ Questions/Q 8554355
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:51:50+00:00 2026-06-11T14:51:50+00:00

var a = function() { function someSetup(){ var setup = ‘done’; } function actualWork()

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var a = function() {
  function someSetup(){
    var setup = 'done';
  }
  function actualWork() {
    alert('Worky-worky');
  }
  someSetup();
  return actualWork;
}();

why the above code doesn’t alert Worky-worky?it shows undefined.thank you

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:51:51+00:00Added an answer on June 11, 2026 at 2:51 pm

    Because you only return the function, not call it.

    Perform a(); after this code execution, this will call the function that’s returned by anonymous self-executing function, thus actualWork.

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