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Home/ Questions/Q 6978173
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:43:16+00:00 2026-05-27T17:43:16+00:00

var foo = { bar: function() { return this.baz; }, baz: 1 }; (function(){

  • 0
  var foo = {
    bar: function() { return this.baz; },
    baz: 1
  };
  (function(){
    return typeof arguments[0]();
  })(foo.bar);

Why does this code return undefined?

I would assume arguments[0] would hold the foo.bar, which is a function. When invoked via arguments[0]() it should return the result of the function evaluation in, this case 1. Hence, typeof arguments[0]() should return “Number” (like typeof 1). Instead, it returns undefined. Why?

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:43:16+00:00Added an answer on May 27, 2026 at 5:43 pm

    this refer to bar function itself.

    var foo = {
        bar: function() {return foo.baz; },
        baz:1
      };
      (function(){
        return typeof arguments[0]();
      })(foo.bar);
    

    fiddle : http://jsfiddle.net/W9Jqb/

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