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Home/ Questions/Q 733207
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:13:50+00:00 2026-05-14T07:13:50+00:00

var grossBrackets = new Array( ‘300’, ‘400’, ‘500’, ‘600’, ‘700’, ‘800’, ‘900’, ‘1000’ );

  • 0
var grossBrackets = new Array( '300', '400', '500', '600', '700', '800', '900', '1000' );   
function bracketSort( itemToSort ) {
        for( index = 0 ; index < grossBrackets.length ; index++ ) {
            if ( itemToSort < grossBrackets[index] ) {
                bracketData[index]++;
            } else if ( itemToSort > grossBrackets[7] ) {
                grossBrackets[7]++;
            }
        }
        return bracketData;
    }

This is my current code, and I basically want to sort the data into their proper brackets. My source code is really long, but when I input these numbers into the function:

200.18
200.27
200.36
200.45
200.54

bracketData prints 5,5,5,5,5,5,5,5 or is there a better way to do this?

Brackets:
<300,
<400,
<500,
<600,
<700,
<800,
<900,
<1000,
greater than 1000

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:13:50+00:00Added an answer on May 14, 2026 at 7:13 am

    If you only want each item to be placed in one bracket, you need to end your loop over grossBrackets once you’ve found a match. You can do this with the break keyword, like so:

    if ( itemToSort < grossBrackets[index] ) {
       bracketData[index]++;
       break;
    } 
    

    Incidentally, you’re checking whether itemToSort is greater than grossBrackets[7] 8 times, one for each element in grossBrackets. You really only need to do this once, so it doesn’t need to be in the loop.

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