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Home/ Questions/Q 3996636
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T07:18:12+00:00 2026-05-20T07:18:12+00:00

var messagetoSend = $.trim(document.getElementById(msgText).value); messagetoSend = messagetoSend.replace(\n, <br />); alert(messagetoSend); Given input: Line 1

  • 0
var messagetoSend = $.trim(document.getElementById("msgText").value);
messagetoSend = messagetoSend.replace("\n", "<br />");
alert(messagetoSend);

Given input:

Line 1


Line 2




Line 3

This alerts:

Line 1<br />


Line 2




Line 3

When I expect it to alert:

Line 1<br /><br /><br />Line 2<br /><br /><br /><br /><br />Line 3
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T07:18:12+00:00Added an answer on May 20, 2026 at 7:18 am

    You need the /g for global matching

    replace(/\n/g, "<br />");

    This works for me for \n – see this answer if you might have \r\n

    NOTE: The dupe is the most complete answer for any combination of \r\n, \r or \n

    var messagetoSend = document.getElementById('x').value.replace(/\n/g, "<br />");
    console.log(messagetoSend);
    <textarea id="x" rows="9">
        Line 1
        
        
        Line 2
        
        
        
        
        Line 3
    </textarea>

    UPDATE

    It seems some visitors of this question have text with the breaklines escaped as

    some text\r\nover more than one line”

    In that case you need to escape the slashes:

    replace(/\\r\\n/g, "<br />");

    NOTE: All browsers will ignore \r in a string when rendering.

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