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Home/ Questions/Q 9021197
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T05:11:55+00:00 2026-06-16T05:11:55+00:00

var name = new Array(‘freddy’, ‘mac’, ‘fanny’, ‘may’); var content = ‘hi ‘.+name[i]+.’!’; $(‘div.class’).each(function

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var name = new Array('freddy', 'mac', 'fanny', 'may');
var content = 'hi '.+name[i]+.'!';

$('div.class').each(function (i) {
this.html(content);
});

This javascript should output
hi freddy!
hi mac!
hi fanny!
hi may!

but there is an error for the var because it refrences an array that has not been set up yet.

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  1. Editorial Team
    Editorial Team
    2026-06-16T05:11:57+00:00Added an answer on June 16, 2026 at 5:11 am

    You are assigning a value to the content variable, and a value is evaluated when you assign the value, not when you use the variable. I.e. a plain value can not contain a reference to another value.

    You can make it a function that evaluates the value when it’s called:

    var name = new Array('freddy', 'mac', 'fanny', 'may');
    var content = function(i) { return 'hi ' + name[i] + '!'};
    
    $('div.class').each(function (i) {
      $(this).html(content(i));
    });
    
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