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Home/ Questions/Q 9038913
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T09:36:22+00:00 2026-06-16T09:36:22+00:00

var obj = {}; var fn = function(){}; obj.prop = some value; fn.prop =

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var obj = {};
var fn = function(){};
obj.prop = "some value";
fn.prop = "some value";
assert( obj.prop == fn.prop, "Both are objects, both have the property." );
assert(typeof(obj) === 'object', "Yes its an object");
assert(typeof(fn) === 'object', "why is this not an object");

I heard from some people around that functions are objects and this is what i am believing so far, but why is the first condition passes well and third one fails.

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  1. Editorial Team
    Editorial Team
    2026-06-16T09:36:23+00:00Added an answer on June 16, 2026 at 9:36 am

    That’s because the direct type of a function is "function".

    However, you missed this assertion:

    fn instanceof Object // true
    

    Btw, types such as "number" and "string" are strictly not descendants of Object, even though they are like objects in the sense that they have methods; just one of those things that makes JavaScript interesting 🙂

    See also: typeof and its range of values.

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