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Home/ Questions/Q 7899519
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:43:24+00:00 2026-06-03T08:43:24+00:00

var parser = new DOMParser(), d = parser.parseFromString(‘<?xml version=1.0?><div class=a>Hello</div>’, ‘application/xhtml+xml’); console.log(d.querySelector(‘*’)); console.log(d.querySelector(‘div’)); console.log(d.querySelector(‘div.a’));

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var 
    parser = new DOMParser(),
    d = parser.parseFromString('<?xml version="1.0"?><div class="a">Hello</div>', 'application/xhtml+xml');

console.log(d.querySelector('*'));
console.log(d.querySelector('div'));
console.log(d.querySelector('div.a'));

The first two selectors work

The last selector…. the class selector…. returns null 🙁

Any ideas why?

Needing this to query html results from AJAX, and dont want to add it to the main DOM to do so.

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:43:26+00:00Added an answer on June 3, 2026 at 8:43 am

    Try it:

    console.log(d.querySelector('div[class=a]'));
    
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