Question

var text = "Price: 123 dollar."
text.replace(/((\d+\.?\d+?)|(\d{1,3}(\,\d{3})+)) *([a-zA-Z]+)/, function(a,b,c){
document.write(a+" | "+b+" | "+c);
return;
}

Now The output is: 123 dollar | 123 | 123

But I need the output to be: 123 dollar | 123 | dollar

It works with the regex /\b((?:\d+.)?\d+) *([a-zA-Z]+)/

Can’t figure it out.. Why b and c are the same?!

Fix: The solution was to remove unnecessary capture groups:

/((?:\d+.?\d+?)|(?:\d{1,3}(?:\,\d{3})+)) *([a-zA-Z]+)/

Thanks @Mythril and @cababunga

Answer 1

Because you created more capture groups. Which means more parameters to the replace function, try this:

var text = "Price: 123 dollar."
text.replace(/((\d+\.?\d+?)|(\d{1,3}(\,\d{3})+)) *([a-zA-Z]+)/, function(a,b,c,d,e,f){
    document.write(a+" | "+b+" | "+f);}
);