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Home/ Questions/Q 592565
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T15:45:11+00:00 2026-05-13T15:45:11+00:00

Version 1: var spamfoo = new Array(); spamfoo.push([‘name’, ‘url’]); spamfoo.push([‘dog’, ‘cat’]); alert(spamfoo); // Alerts:

  • 0

Version 1:

var spamfoo = new Array();
spamfoo.push(['name', 'url']);
spamfoo.push(['dog', 'cat']);
alert(spamfoo);
// Alerts: name,url,dog,cat
alert(spamfoo.length);
// Alerts: 2
// ??? (shouldn't this be 4?)

Version 2:

var spamfoo = new Array();
spamfoo.push(['name', 'url']);
spamfoo = spamfoo + ['dog', 'cat'];
alert(spamfoo);
// Alerts: name,url,dog,cat
alert(spamfoo.length);
// Alerts: 15
// ??? (this one I wasn't sure about anyways because I didn't know if you could add an array)

How is this possible? Doesn’t ['value', 'value'] make an array and doesn’t?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T15:45:11+00:00Added an answer on May 13, 2026 at 3:45 pm

    The answer is that my_array.length does work but you’re missing some of the implicit type conversions that are happening and what push() does.

    In the first example, you are creating a multidimensional array. Technically it’s an array of arrays rather than a true multidimensional array. The first code snippet creates this array of arrays:

    [
      ["name", "url"],
      ["dog", "cat"]
    ]
    

    which is of length 2 so that result is correct.

    The second example’s use of the concatenation operator + converts spamfoo to a string, which means that length is now returning the string length. The string length is 15 so this too is correct.

    You might want to add this line to your examples:

    alert(typeof spamfoo);
    

    If so you’ll see the first example displays object and the second displays string.

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