Question

very simple question, i have this:

$datos1=mysql_query("SELECT TIMEDIFF(NOW(), '" . $row['fecha'] . "');");
echo($datos1);

But the result is: Resource id #6

How can i print the result in the way is meant to be? Thanks!

Answer 1

You need to use a fetch function. for example:

$result = mysql_query(sprintf("SELECT TIMEDIFF(NOW(), '%s') as time_delta", $row['fecha']));
if($result){
  $data = mysql_fetch_assoc($result);
  echo $data['time_delta'];
}

However, i wouldnt use the mysql functions unless absolutely necessary. the mysql extension is NOT recommended for use in new projects. Instead you should use PDO with PDO_mysql or mysqli.