Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6921591
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T10:17:48+00:00 2026-05-27T10:17:48+00:00

(Visual) C++ world. I have a tree structure, want to visualize it. More specifically:

  • 0

(Visual) C++ world. I have a tree structure, want to visualize it. More specifically:

I have a tree data. I want the library that processes this data and computes coordinates (in any logical coordinate space, say 2000×2000 logical pixels) for each nodes, AND for each lines connecting them. Line connecting the two nodes might not be a simple straight line, it might be curve or some sort of path consisting of straight line segments. Ideally I’d like the line defining path to be calculated for the given tree nodes’ coordinates as well, in case the user will drag and rearrange the nodes.

Shortly, I need the library that will compute all the necessary geometrical coordinates for me, for the given graph. Then I’ll use these coordinates to draw the graph as I wish, using GDI.

I’ve heard of Graphviz, dot-language, and such. But I’m not sure whether it (or its alternatives like OGDF or igraph) can do what I want. The idea I want to accomplish is to render the graph myself, but need the assistance in generating coordinates. Also user must be able to reposition the nodes, so the re-computation of line path that connects rearranged nodes must be possible, so that e.g. lines do not cross any existing nodes.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T10:17:49+00:00Added an answer on May 27, 2026 at 10:17 am

    Yes, graphviz can do this.

    Layout a directed graph

    Let’s say you have the following graph in tree.gv:

    digraph g{
      a[label="I"];
      b[label="am"];
      c[label="a"];
      d[label="tree"];
      e[label="with"];
      f[label="7"];
      g[label="nodes"];
    
      a -> b -> c;
      b -> d -> e;
      d -> f;
      d -> g;
    }
    

    dot can lay out this graph: dot tree.gv which results in

    digraph g {
        node [label="\N"];
        graph [bb="0,0,208,252"];
        a [label=I, pos="63,234", width="0.75", height="0.5"];
        b [label=am, pos="63,162", width="0.75", height="0.5"];
        c [label=a, pos="27,90", width="0.75", height="0.5"];
        d [label=tree, pos="99,90", width="0.75", height="0.5"];
        e [label=with, pos="27,18", width="0.75", height="0.5"];
        f [label=7, pos="99,18", width="0.75", height="0.5"];
        g [label=nodes, pos="176,18", width="0.89579", height="0.5"];
        a -> b [pos="e,63,180.1 63,215.7 63,207.98 63,198.71 63,190.11"];
        b -> c [pos="e,35.304,107.15 54.65,144.76 50.288,136.28 44.853,125.71 39.959,116.2"];
        b -> d [pos="e,90.696,107.15 71.35,144.76 75.712,136.28 81.147,125.71 86.041,116.2"];
        d -> e [pos="e,41.796,33.385 84.43,74.834 74.25,64.938 60.476,51.546 48.969,40.359"];
        d -> f [pos="e,99,36.104 99,71.697 99,63.983 99,54.712 99,46.112"];
        d -> g [pos="e,159.91,33.626 114.58,74.834 125.4,65.003 140,51.723 152.26,40.582"];
    }
    

    All the coordinates can be found in the output. If you need even more details on how to draw the graph, you may try using the xdot format: dot -Txdot tree.gv

    digraph g {
        node [label="\N"];
        graph [bb="0,0,208,252",
            _draw_="c 9 -#ffffffff C 9 -#ffffffff P 4 0 -1 0 252 209 252 209 -1 ",
            xdotversion="1.2"];
        a [label=I, pos="63,234", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 63 234 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 63 228 0 5 1 -I "];
        b [label=am, pos="63,162", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 63 162 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 63 156 0 17 2 -am "];
        c [label=a, pos="27,90", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 27 90 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 27 84 0 7 1 -a "];
        d [label=tree, pos="99,90", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 99 90 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 99 84 0 21 4 -tree "];
        e [label=with, pos="27,18", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 27 18 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 27 12 0 24 4 -with "];
        f [label=7, pos="99,18", width="0.75", height="0.5", _draw_="c 9 -#000000ff e 99 18 27 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 99 12 0 7 1 -7 "];
        g [label=nodes, pos="176,18", width="0.89579", height="0.5", _draw_="c 9 -#000000ff e 176 18 32 18 ", _ldraw_="F 14.000000 11 -Times-Roman c 9 -#000000ff T 176 12 0 34 5 -nodes "];
        a -> b [pos="e,63,180.1 63,215.7 63,207.98 63,198.71 63,190.11", _draw_="c 9 -#000000ff B 4 63 216 63 208 63 199 63 190 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 67 190 63 180 60 190 "];
        b -> c [pos="e,35.304,107.15 54.65,144.76 50.288,136.28 44.853,125.71 39.959,116.2", _draw_="c 9 -#000000ff B 4 55 145 50 136 45 126 40 116 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 43 114 35 107 37 118 "];
        b -> d [pos="e,90.696,107.15 71.35,144.76 75.712,136.28 81.147,125.71 86.041,116.2", _draw_="c 9 -#000000ff B 4 71 145 76 136 81 126 86 116 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 89 118 91 107 83 114 "];
        d -> e [pos="e,41.796,33.385 84.43,74.834 74.25,64.938 60.476,51.546 48.969,40.359", _draw_="c 9 -#000000ff B 4 84 75 74 65 60 52 49 40 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 51 38 42 33 47 43 "];
        d -> f [pos="e,99,36.104 99,71.697 99,63.983 99,54.712 99,46.112", _draw_="c 9 -#000000ff B 4 99 72 99 64 99 55 99 46 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 103 46 99 36 96 46 "];
        d -> g [pos="e,159.91,33.626 114.58,74.834 125.4,65.003 140,51.723 152.26,40.582", _draw_="c 9 -#000000ff B 4 115 75 125 65 140 52 152 41 ", _hdraw_="S 5 -solid c 9 -#000000ff C 9 -#000000ff P 3 155 43 160 34 150 38 "];
    }
    

    Detailed information about this format can be found on the graphviz web site.

    Layout only edges / recompute edges

    You may use one of the above outputs, modify positions of any nodes, and use it as input for the following command:

    neato -n tree.modified.gv
    

    This will recompute only the edges (more information on neato dot and neato options can be found on their manual pages).

    Below you can see an example of an unmodified and a modified layout – I changed positions for the b and g nodes.

    Automatic layout:

    Autolayout

    Modified layout:

    Modified layout

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a tree of data that I would like to present to the
I have created a Hello World web part. When I pressed F5 in Visual
I currently have this line of code which I want to work in all
I have a visual studio 2008 project in the directory like C:\Users\espl\Desktop\hello\world\helloworld(.sln file) Now
Does Visual Studio .NET have a way to toggle word-wrap on and off? I
I have a Visual Studio 2008 solution with two projects (a Word-Template project and
I have been forced to work in Visual Studio 2005 and would like to
I have successfully used the Excel and Word addin templates in Visual studio 2008
What would a developer used to working in Visual Studio have to give up
I have a Visual Studio 2008 solution, and I would like to include a real folder

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.