Question

void g(int& a)
{
    std::cout<<"int&\n";
} 

void g(int a)
{
    std::cout<<"int\n";
}  

int main()
{    
    int a = 2;   
    g(a); //won't compile (at least under MSVC 2012)

    std::cin.ignore();
}

Is there a way to avoid ambiguous call error here ? something like g( static_cast<int&>(a) );

Answer 1

If you can cast, there is, of course a way to disambiguate the call:

g(const_cast<int const&>(a));

If you insist to call the reference version, the resolution is a bit more tricky:

static_cast<void(*)(int&)>(g)(a);