Question

void (int a[]) { a[5] = 3; // this is wrong? }

Can I do this so that the array that is passed in is modified?

Sorry for deleting, a bit new here…

I have another question which might answer my question:

If I have

void Test(int a) { }  void Best(int &a) { } 

are these two statements equivalent?

Test(a); Best(&a); 

Answer 1

void Test(int a[])  {     a[5] = 3; } 

just alternate syntax for:

void Test(int* a)  {     *(a+5) = 3; } 

No array is passed, just a pointer. The original array is modified.

As for your second revision, given:

void Test(int a)  { }  void Best(int &a)  { } 

then

Test(aa);      // Passes aa by value.  Changes to a in Test() do not effect aa Best(aa);      // Passes aa by reference; Changes to a DO effect aa Best(&aa);     // Is a syntax error: Passing a pointer instead of an int.