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Home/ Questions/Q 3841814
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T15:42:19+00:00 2026-05-19T15:42:19+00:00

void main() { if(a == a) printf(Yes, equal); else printf(No, not equal); } Why

  • 0
void main() {
    if("a" == "a")
      printf("Yes, equal");  
    else
      printf("No, not equal");
}

Why is the output No, not equal?

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  1. Editorial Team
    Editorial Team
    2026-05-19T15:42:19+00:00Added an answer on May 19, 2026 at 3:42 pm

    What you are comparing are the two memory addresses for the different strings, which are stored in different locations. Doing so essentially looks like this:

    if(0x00403064 == 0x002D316A) // Two memory locations
    {
        printf("Yes, equal");
    }
    

    Use the following code to compare two string values:

    #include <string.h>
    
    ...
    
    if(strcmp("a", "a") == 0)
    {
        // Equal
    }
    

    Additionally, "a" == "a" may indeed return true, depending on your compiler, which may combine equal strings at compile time into one to save space.

    When you’re comparing two character values (which are not pointers), it is a numeric comparison. For example:

    'a' == 'a' // always true
    
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